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Exercise

$\frac{d}{dx}\left(-2^y\:+\:24y^-5\:\right)\left(y+4y^3\right)+\left(y^-2-6y^-4\right)\left(1+12y^2\right)$

Step-by-step Solution

1

The derivative of the constant function ($\left(- 2^y+24y^{-5}\right)\left(y+4y^3\right)+\left(y^{-2}-6y^{-4}\right)\left(1+12y^2\right)$) is equal to zero

0

Final answer to the exercise

0

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  • Find the derivative using the definition
  • Find the derivative using the product rule
  • Find the derivative using the quotient rule
  • Find the derivative using logarithmic differentiation
  • Find the derivative
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
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Main Topic: Constant Rule for Differentiation

The constant rule for differentiation says that the derivative for any constant $k$ is equal to zero.

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