Solve the differential equation $xy^{\prime}-y=y^3$

Step-by-step Solution

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Final answer to the problem

$\ln\left|y\right|-\frac{1}{2}\ln\left|y^2+1\right|=\ln\left|x\right|+C_0$
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Step-by-step Solution

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  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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Rewrite the differential equation using Leibniz notation

$x\frac{dy}{dx}-y=y^3$

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$x\frac{dy}{dx}-y=y^3$

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Unlock the first 3 steps of this solution

Learn how to solve problems step by step online. Solve the differential equation xy^'-y=y^3. Rewrite the differential equation using Leibniz notation. We need to isolate the dependent variable y, we can do that by simultaneously subtracting -y from both sides of the equation. Multiply -1 times -1. Group the terms of the differential equation. Move the terms of the y variable to the left side, and the terms of the x variable to the right side of the equality.

Final answer to the problem

$\ln\left|y\right|-\frac{1}{2}\ln\left|y^2+1\right|=\ln\left|x\right|+C_0$

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Function Plot

Plotting: $\ln\left(y\right)-\frac{1}{2}\ln\left(y^2+1\right)=\ln\left(x\right)+C_0$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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