Final answer to the problem
$\frac{-1- +4}{\left|16- +4^2\right|\sqrt[3]{12- +4^2}}$
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Step-by-step Solution
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1
Evaluate the limit $\lim_{x\to+4}\left(\frac{-x^3+4x^2-x-4}{\sqrt[3]{12-x^2}\left|16-x^2\right|}\right)$ by replacing all occurrences of $x$ by $+4$
Learn how to solve limits by direct substitution problems step by step online.
$\frac{- +4^3+4\cdot +4^2- +4-4}{\left|16- +4^2\right|\sqrt[3]{12- +4^2}}$
Learn how to solve limits by direct substitution problems step by step online. Find the limit of (-x^3+4x^2-x+-4)/(abs(16-x^2)(12-x^2)^(1/3)) as x approaches +4. Evaluate the limit \lim_{x\to+4}\left(\frac{-x^3+4x^2-x-4}{\sqrt[3]{12-x^2}\left|16-x^2\right|}\right) by replacing all occurrences of x by +4. Combining like terms - +4^3 and 4\cdot +4^2. Subtract the values 3 and -4.
Final answer to the problem
$\frac{-1- +4}{\left|16- +4^2\right|\sqrt[3]{12- +4^2}}$
