$\frac{d}{dx}arccot\sqrt{x}$
$\int\left(\left(x+1\right)\sqrt{3-x}\right)dx$
$\lim_{x\to\infty}\left(\frac{x}{1-x}\right)$
$\lim_{x\to\infty}\left(\frac{ln\left(x^{12}\right)}{7x}\right)$
$\lim_{x\to-\infty}\frac{4x^4-7x^3}{\left(x^2-1\right)}$
$8x-5\left(4x-1\right)\ge\:-1+2\left(4x-3\right)$
$1017\:-\:7776$
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