Solve the product $\left(a^{\left(x+1\right)}- 26^{\left(x-1\right)}\right)\left(26^{\left(x-1\right)}+a^{\left(x+1\right)}\right)$

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Final answer to the problem

$a^{\left(2x+2\right)}- 26^{\left(2x-2\right)}$
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Step-by-step Solution

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The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.

Learn how to solve factor by difference of squares problems step by step online.

$\left(a^{\left(x+1\right)}\right)^2-\left(26^{\left(x-1\right)}\right)^2$

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Learn how to solve factor by difference of squares problems step by step online. Solve the product (a^(x+1)-*26^(x-1))(26^(x-1)+a^(x+1)). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Simplify \left(a^{\left(x+1\right)}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals x+1 and n equals 2. Simplify \left(26^{\left(x-1\right)}\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals x-1 and n equals 2. Multiply the single term 2 by each term of the polynomial \left(x+1\right).

Final answer to the problem

$a^{\left(2x+2\right)}- 26^{\left(2x-2\right)}$

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Plotting: $a^{\left(2x+2\right)}- 26^{\left(2x-2\right)}$

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a
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g
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x
y
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(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Factor by Difference of Squares

The difference of two squares is a squared number subtracted from another squared number. Every difference of squares may be factored according to the identity a^2-b^2=(a+b)(a-b) in elementary algebra.

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