$\frac{dy}{dx}-2xy=0$
$\frac{9a^4b^2-16a^2b^6}{3a^2b+4ab^3}$
$\frac{d}{dy}\left(cos\left(3ye^x\right)\right)$
$9^3\cdot9^5$
$\left(3x+3\right)\left(5x-2\right)$
$\int\:\:cosx\left(3senx+5\right)dx$
$\frac{dx}{dy}=\frac{1+y}{1+x}$
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