Final answer to the problem
$f\left(x\right)=\left(3x^3-5x^2+2x-11\right)^3\left(25x^{6}+x^{4}+1-10x^{5}+10x^3-2x^2\right)$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Expand the trinomial using the formula $\left(a+b+c\right)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc$
Learn how to solve square of a trinomial problems step by step online.
$f\left(x\right)=\left(3x^3-5x^2+2x-11\right)^3\left(5x^3\right)^2+\left(-x^2\right)^2+1^2+2\cdot 5\cdot -1x^3x^2+2\cdot 5\cdot 1x^3+2\cdot - 1x^2$
Learn how to solve square of a trinomial problems step by step online. Simplify the expression f(x)=(3x^3-5x^22x+-11)^3(5x^3-x^2+1)^2. Expand the trinomial using the formula \left(a+b+c\right)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc. Any expression multiplied by 1 is equal to itself. Any expression multiplied by 1 is equal to itself. Multiply 2 times 5.
Final answer to the problem
$f\left(x\right)=\left(3x^3-5x^2+2x-11\right)^3\left(25x^{6}+x^{4}+1-10x^{5}+10x^3-2x^2\right)$
