Final answer to the problem
$y=\frac{\sqrt[3]{x+2}\sqrt[3]{x^{2}-2x+4}\sqrt{x^2+1}}{2x^6+7x-4}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Differential
- Find the derivative
- Find the integral
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
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1
Factor the sum or difference of cubes using the formula: $a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2)$
Learn how to solve factorization problems step by step online.
$y=\frac{\sqrt[3]{\left(\sqrt[3]{x^3}+\sqrt[3]{8}\right)\left(\sqrt[3]{\left(x^3\right)^{2}}-\sqrt[3]{8}\sqrt[3]{x^3}+\sqrt[3]{\left(8\right)^{2}}\right)}\sqrt{x^2+1}}{2x^6+7x-4}$
Learn how to solve factorization problems step by step online. Solve the rational equation y=((x^3-8)^(1/3)(x^2+1)^(1/2))/(2x^6+7x+-4). Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). Calculate the power \sqrt[3]{8}. Calculate the power \sqrt[3]{8}. Multiply -1 times 2.
Final answer to the problem
$y=\frac{\sqrt[3]{x+2}\sqrt[3]{x^{2}-2x+4}\sqrt{x^2+1}}{2x^6+7x-4}$
