$3x^3+6x^2+3x$
$\frac{d}{dx}x^y=y^x$
$\frac{2}{3^{n+1}}+\frac{\left(-1\right)^n}{5^n}$
$x^2+xy+yx+y^2$
$\left(d-3b\right)^3$
$3x+5y+8x-9y+4x-8y-5x+4y$
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