$2^{8x-2}=4^{4x+1}$
$\int t^2e^xdx$
$\frac{\left(-9\right).\left(-8\right)+\left(-4\right).\left(-10\right)}{\left(-8\right)}$
$115\cdot6$
$\int\left(2x^2-1\right)e^{-x}dx$
$\lim_{x\to\infty}\left(\frac{\sqrt[3]{x^2+2}}{3x+1}\right)$
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