$4=256$
$\left(x-5\right)\left(x+3\right)\left(x-4\right)\left(x+2\right)$
$\frac{x^3-2x^2+16x-8}{x+2}$
$y+\frac{2}{5}y$
$\left(x^2+4\right)dy\:=\:\left(2x-8\right)dx$
$\left(x^2+y\right)dx+\left(x+e^y\right)dy=0$
$7-\left(-19\right)-18+-19$
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