$1x+4-5x+6$
$\frac{dy}{dx}-5y=5x$
$\frac{\left(3x+6\right)}{8}=\frac{\left(3x-3\right)}{16}$
$\left(4x\right)\left(12x\right)$
$\lim_{x\to-9}\left(\frac{2\sqrt{x-6}}{x-9}\right)$
$\int\frac{1}{\left(1-\sqrt{y}\right)^2}dy$
$16m^2-196^2$
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