$\frac{x^3+5x^2-7x+3}{x-1}$
$4a-1\cdot3a+2$
$2^3\cdot2^{-5}$
$5g^2+6g-4g+8g^5$
$2\cdot2048$
$\left(5+7\right)-\left(6+5\right)$
$\frac{sin^2\left(x\right)}{cos^2\left(x\right)}=tan^2\left(x\right)$
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