Final answer to the problem
$x\leq 2x^2-2ax-x+a+2$
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Step-by-step Solution
How should I solve this problem?
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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
Moving the denominator multiplying to the other side of the inequation
$x-2\leq \left(2x-1\right)\left(x-a\right)$
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$x-2\leq \left(2x-1\right)\left(x-a\right)$
Learn how to solve problems step by step online. Solve the inequality (x-2)/(x-a)<=2x-1. Moving the denominator multiplying to the other side of the inequation. Moving the term -2 to the other side of the inequation with opposite sign. Multiply the single term x-a by each term of the polynomial \left(2x-1\right). Simplify the product -(x-a).
Final answer to the problem
$x\leq 2x^2-2ax-x+a+2$
