Final answer to the problem
$x\geq \frac{12x-18y}{7}+3$
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Step-by-step Solution
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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
Divide both sides of the inequation by $7$
$x-3\geq \frac{6\left(2x-3y\right)}{7}$
Learn how to solve limits by direct substitution problems step by step online.
$x-3\geq \frac{6\left(2x-3y\right)}{7}$
Learn how to solve limits by direct substitution problems step by step online. Solve the inequality 7(x-3)>=6(2x-3y). Divide both sides of the inequation by 7. Multiply the single term 6 by each term of the polynomial \left(2x-3y\right). Moving the term -3 to the other side of the inequation with opposite sign.
Final answer to the problem
$x\geq \frac{12x-18y}{7}+3$
