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The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.
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$\sec\left(x\right)^2-\left(\tan\left(x\right)+1\right)^2=\frac{2}{1-\csc\left(x\right)^2}$
Learn how to solve problems step by step online. Solve the trigonometric equation (sec(x)-tan(x)+-1)(sec(x)+tan(x)+1)=2/(1-csc(x)^2). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Apply the trigonometric identity: 1-\csc\left(\theta \right)^2=-\cot\left(\theta \right)^2. Applying the trigonometric identity: \frac{1}{\cot\left(\theta\right)}=\tan\left(\theta\right). Multiply 2 times -1.
