Find the implicit derivative $\frac{d}{dx}\left(2\sin\left(x\right)\cos\left(x\right)\right)=1$

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Final answer to the problem

$2\cos\left(2x\right)=1$
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Step-by-step Solution

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The derivative of a function multiplied by a constant is equal to the constant times the derivative of the function

Learn how to solve product rule of differentiation problems step by step online.

$2\frac{d}{dx}\left(\sin\left(x\right)\cos\left(x\right)\right)=1$

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Learn how to solve product rule of differentiation problems step by step online. Find the implicit derivative d/dx(2sin(x)cos(x))=1. The derivative of a function multiplied by a constant is equal to the constant times the derivative of the function. Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g', where f=\sin\left(x\right) and g=\cos\left(x\right). The derivative of the sine of a function is equal to the cosine of that function times the derivative of that function, in other words, if {f(x) = \sin(x)}, then {f'(x) = \cos(x)\cdot D_x(x)}. When multiplying two powers that have the same base (\cos\left(x\right)), you can add the exponents.

Final answer to the problem

$2\cos\left(2x\right)=1$

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Plotting: $2\cos\left(2x\right)=1$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Product Rule of differentiation

The product rule is a formula used to find the derivatives of products of two or more functions. It may be stated as $(f\cdot g)'=f'\cdot g+f\cdot g'$

Used Formulas

See formulas (5)

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