Final answer to the problem
$\frac{\left(2^{\left(n+5\right)}+2^{\left(n+2\right)}\right)^{4}}{\left(2^{\left(n+4\right)}+2^{\left(n+2\right)}- 2^{\left(n+3\right)}\right)^{4}}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Load more...
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1
Since the exponent is negative, we can invert the fraction
$\left(\frac{2^{\left(n+5\right)}+2^{\left(n+2\right)}}{2^{\left(n+4\right)}+2^{\left(n+2\right)}- 2^{\left(n+3\right)}}\right)^{4}$
2
The power of a quotient is equal to the quotient of the power of the numerator and denominator: $\displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}$
$\frac{\left(2^{\left(n+5\right)}+2^{\left(n+2\right)}\right)^{4}}{\left(2^{\left(n+4\right)}+2^{\left(n+2\right)}- 2^{\left(n+3\right)}\right)^{4}}$
Final answer to the problem
$\frac{\left(2^{\left(n+5\right)}+2^{\left(n+2\right)}\right)^{4}}{\left(2^{\left(n+4\right)}+2^{\left(n+2\right)}- 2^{\left(n+3\right)}\right)^{4}}$
