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- Integrate by partial fractions
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Rewrite the expression $\frac{3x^2+6x+7}{x^3-9x}$ inside the integral in factored form
Learn how to solve integrals by partial fraction expansion problems step by step online.
$\int\frac{3x^2+6x+7}{x\left(x+3\right)\left(x-3\right)}dx$
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((3x^2+6x+7)/(x^3-9x))dx. Rewrite the expression \frac{3x^2+6x+7}{x^3-9x} inside the integral in factored form. Rewrite the fraction \frac{3x^2+6x+7}{x\left(x+3\right)\left(x-3\right)} in 3 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{-7}{9x}+\frac{8}{9\left(x+3\right)}+\frac{26}{9\left(x-3\right)}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{-7}{9x}dx results in: -\frac{7}{9}\ln\left(x\right).