Factor the difference of squares $x^2-25$ as the product of two conjugated binomials
Simplify the fraction $\frac{\left(x+5\right)\left(x-5\right)}{x-5}$ by $x-5$
Evaluate the limit $\lim_{x\to5}\left(x+5\right)$ by replacing all occurrences of $x$ by $5$
Add the values $5$ and $5$
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