Find the limit of $\frac{2x+1}{4x^2}$ as $x$ approaches $\infty $

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As it's an indeterminate limit of type $\frac{\infty}{\infty}$, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is

$\lim_{x\to\infty }\left(\frac{\frac{2x+1}{x^2}}{\frac{4x^2}{x^2}}\right)$

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$\lim_{x\to\infty }\left(\frac{\frac{2x+1}{x^2}}{\frac{4x^2}{x^2}}\right)$

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Learn how to solve limits to infinity problems step by step online. Find the limit of (2x+1)/(4x^2) as x approaches infinity. As it's an indeterminate limit of type \frac{\infty}{\infty}, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is . Separate the terms of both fractions. Simplify the fraction \frac{4x^2}{x^2} by x^2. Simplify the fraction by x.

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Function Plot

Plotting: $\frac{2x+1}{4x^2}$

Main Topic: Limits to Infinity

The limit of a function f(x) when x tends to infinity is the value that the function takes as the value of x grows indefinitely.

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