Find the limit of $\frac{4x^5+2x^2-3x^7}{x\left(2x^3+2\right)^2}$ as $x$ approaches $\infty $

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Final answer to the problem

indeterminate

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Evaluate the limit $\lim_{x\to\infty }\left(\frac{4x^5+2x^2-3x^7}{x\left(2x^3+2\right)^2}\right)$ by replacing all occurrences of $x$ by $\infty $

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$\frac{4\cdot \infty ^5+2\cdot \infty ^2-3\cdot \infty ^7}{\infty \cdot \left(2\cdot \infty ^3+2\right)^2}$

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Learn how to solve problems step by step online. Find the limit of (4x^5+2x^2-3x^7)/(x(2x^3+2)^2) as x approaches infinity. Evaluate the limit \lim_{x\to\infty }\left(\frac{4x^5+2x^2-3x^7}{x\left(2x^3+2\right)^2}\right) by replacing all occurrences of x by \infty . Infinity to the power of any positive number is equal to infinity, so \infty ^2=\infty. Infinity to the power of any positive number is equal to infinity, so \infty ^7=\infty. Infinity to the power of any positive number is equal to infinity, so \infty ^5=\infty.

Final answer to the problem

indeterminate

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Plotting: $\frac{4x^5+2x^2-3x^7}{x\left(2x^3+2\right)^2}$

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