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Divide $6x^5-17x^4+7^3+5x^2+3x+2$ by $3x^3-4x^2+5x-7$

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Solution

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Final answer to the problem

$\frac{6x^5-17x^4+345+5x^2+3x}{3x^3-4x^2+5x-7}$
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Step-by-step Solution

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  • Write in simplest form
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
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1

Calculate the power $7^3$

Learn how to solve trigonometric integrals problems step by step online.

$\frac{6x^5-17x^4+343+5x^2+3x+2}{3x^3-4x^2+5x-7}$

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Learn how to solve trigonometric integrals problems step by step online. Divide 6x^5-17x^47^35x^23x+2 by 3x^3-4x^25x+-7. Calculate the power 7^3. Add the values 343 and 2.

Final answer to the problem

$\frac{6x^5-17x^4+345+5x^2+3x}{3x^3-4x^2+5x-7}$

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Function Plot

Plotting: $\frac{6x^5-17x^4+345+5x^2+3x}{3x^3-4x^2+5x-7}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Trigonometric Integrals

Integrals that contain trigonometric functions and their powers.

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