Final answer to the problem
$x^{10}-x^{8}-2x^{6}+2x^{4}+x^2-1$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Product of Binomials with Common Term
- FOIL Method
- Find the integral
- Find the derivative
- Factor
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Load more...
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1
Multiply the single term $x^4-x^2+1$ by each term of the polynomial $\left(x^6-1\right)$
Learn how to solve special products problems step by step online.
$x^6\left(x^4-x^2+1\right)-\left(x^4-x^2+1\right)-3x^2\left(x^3+x^2\right)\left(x-1\right)$
Learn how to solve special products problems step by step online. Expand the expression (x^6-1)(x^4-x^2+1)-3x^2(x^3+x^2)(x-1). Multiply the single term x^4-x^2+1 by each term of the polynomial \left(x^6-1\right). Multiply the single term x^6 by each term of the polynomial \left(x^4-x^2+1\right). When multiplying exponents with same base we can add the exponents. When multiplying exponents with same base we can add the exponents.
Final answer to the problem
$x^{10}-x^{8}-2x^{6}+2x^{4}+x^2-1$
