Final answer to the problem
$\sqrt{3}$
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Step-by-step Solution
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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
To rationalize the denominator of the fraction, we multiply the numerator and denominator by $2\sqrt{3}$
$\frac{6}{2\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}$
Learn how to solve rationalisation problems step by step online.
$\frac{6}{2\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}$
Learn how to solve rationalisation problems step by step online. Rationalize and simplify the expression 6/(23^(1/2)). To rationalize the denominator of the fraction, we multiply the numerator and denominator by 2\sqrt{3}. Multiplying fractions \frac{6}{2\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}. When multiplying two powers that have the same base (\sqrt{3}), you can add the exponents. Cancel the fraction's common factor 2.
Final answer to the problem
$\sqrt{3}$
Exact Numeric Answer
$1.732051$
