Expand the expression $\left(2x^3y^2-7x^2y^4\right)\left(7x^3y^2-5x^2y^4\right)$

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Final answer to the problem

$14x^{6}y^{4}-59x^{5}y^{6}+35x^{4}y^{8}$
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Step-by-step Solution

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  • Product of Binomials with Common Term
  • FOIL Method
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Multiply the single term $7x^3y^2-5x^2y^4$ by each term of the polynomial $\left(2x^3y^2-7x^2y^4\right)$

$2x^3y^2\left(7x^3y^2-5x^2y^4\right)-7x^2y^4\left(7x^3y^2-5x^2y^4\right)$

Learn how to solve special products problems step by step online.

$2x^3y^2\left(7x^3y^2-5x^2y^4\right)-7x^2y^4\left(7x^3y^2-5x^2y^4\right)$

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Learn how to solve special products problems step by step online. Expand the expression (2x^3y^2-7x^2y^4)(7x^3y^2-5x^2y^4). Multiply the single term 7x^3y^2-5x^2y^4 by each term of the polynomial \left(2x^3y^2-7x^2y^4\right). Multiply the single term 2x^3y^2 by each term of the polynomial \left(7x^3y^2-5x^2y^4\right). When multiplying exponents with same base we can add the exponents. When multiplying two powers that have the same base (y^2), you can add the exponents.

Final answer to the problem

$14x^{6}y^{4}-59x^{5}y^{6}+35x^{4}y^{8}$

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Function Plot

Plotting: $14x^{6}y^{4}-59x^{5}y^{6}+35x^{4}y^{8}$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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