Final answer to the problem
$y=\frac{\sqrt[3]{x^2-8}\sqrt{x+1}\sqrt{x^{2}-x+1}}{x^6-7x+5}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Differential
- Find the derivative
- Find the integral
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
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1
Factor the sum or difference of cubes using the formula: $a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2)$
Learn how to solve integrals of rational functions problems step by step online.
$y=\frac{\sqrt[3]{x^2-8}\sqrt{\left(\sqrt[3]{x^3}+\sqrt[3]{1}\right)\left(\sqrt[3]{\left(x^3\right)^{2}}-\sqrt[3]{1}\sqrt[3]{x^3}+\sqrt[3]{\left(1\right)^{2}}\right)}}{x^6-7x+5}$
Learn how to solve integrals of rational functions problems step by step online. Solve the rational equation y=((x^2-8)^(1/3)(x^3+1)^(1/2))/(x^6-7x+5). Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). Calculate the power \sqrt[3]{1}. Calculate the power \sqrt[3]{1}. Multiply -1 times 1.
Final answer to the problem
$y=\frac{\sqrt[3]{x^2-8}\sqrt{x+1}\sqrt{x^{2}-x+1}}{x^6-7x+5}$
