Solve the equation $x^3-8y^6=\left(x+2y^2\right)\left(x^2-2xy^2+4y^4\right)$

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Final answer to the problem

true

Step-by-step Solution

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  • Solve for x
  • Solve for y
  • Find the derivative
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  • Find dy/dx
  • Derivative
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  • Solve by quadratic formula (general formula)
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1

Divide both sides of the equation by $x+2y^2$

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$\frac{x^3-8y^6}{x+2y^2}=x^2-2xy^2+4y^4$

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Learn how to solve problems step by step online. Solve the equation x^3-8y^6=(x+2y^2)(x^2-2xy^24y^4). Divide both sides of the equation by x+2y^2. Move everything to the left hand side of the equation. Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). Simplify the fraction \frac{\left(x+2y^{2}\right)\left(x^{2}-2xy^{2}+4y^{4}\right)}{x+2y^2} by x+2y^{2}.

Final answer to the problem

true

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