Final answer to the problem
true
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for x
- Solve for y
- Find the derivative
- Solve by implicit differentiation
- Solve for y'
- Find dy/dx
- Derivative
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
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1
Divide both sides of the equation by $x+2y^2$
$\frac{x^3-8y^6}{x+2y^2}=x^2-2xy^2+4y^4$
Learn how to solve problems step by step online.
$\frac{x^3-8y^6}{x+2y^2}=x^2-2xy^2+4y^4$
Learn how to solve problems step by step online. Solve the equation x^3-8y^6=(x+2y^2)(x^2-2xy^24y^4). Divide both sides of the equation by x+2y^2. Move everything to the left hand side of the equation. Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). Simplify the fraction \frac{\left(x+2y^{2}\right)\left(x^{2}-2xy^{2}+4y^{4}\right)}{x+2y^2} by x+2y^{2}.
Final answer to the problem
true
