Final answer to the problem
$i\left(x\right)=x\left(x^2+3x-4\right)\left(x-2\right)$
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Step-by-step Solution
How should I solve this problem?
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- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
The product of two binomials of the form $(x+a)(x+b)$ is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: $(x+a)(x+b)=x^2+(a+b)x+ab$
$i\left(x\right)=x\left(x^2+\left(-1+4\right)x-4\right)\left(x-2\right)$
2
Subtract the values $4$ and $-1$
$i\left(x\right)=x\left(x^2+3x-4\right)\left(x-2\right)$
Final answer to the problem
$i\left(x\right)=x\left(x^2+3x-4\right)\left(x-2\right)$
