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Express the numbers in the equation as logarithms of base $8$
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$\log_{8}\left(x+6\right)=\log_{8}\left(8^{1}\right)-\log_{8}\left(x+4\right)$
Learn how to solve problems step by step online. Solve the logarithmic equation log8(x+6)=1-log8(x+4). Express the numbers in the equation as logarithms of base 8. Any expression to the power of 1 is equal to that same expression. The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b.