$\int_0^{\infty}\left(\frac{1}{x^2}\right)dx$
$\int_0^1\left(\frac{3}{x^5}\right)dx$
$\int_1^{\infty}\left(\frac{1}{x^2}\right)dx$
$\int_1^{\infty}\left(\frac{ln\left(x\right)}{x}\right)dx$
$\int_1^{\infty}\left(\frac{lnx}{x}\right)dx$
$\int_1^{\infty}\left(\frac{1}{x^3}\right)dx$
$\int_{-\infty}^0\left(\frac{1}{\sqrt{3-x}}\right)dx$
Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b
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