Factor the expression $3x^2+19x+20$

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Final answer to the problem

$\left(x+5\right)\left(3x+4\right)$
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Step-by-step Solution

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  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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1

Factor the trinomial $3x^2+19x+20$ of the form $ax^2+bx+c$, first, make the product of $3$ and $20$

$\left(3\right)\left(20\right)=60$

Learn how to solve polynomial factorization problems step by step online.

$\left(3\right)\left(20\right)=60$

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Learn how to solve polynomial factorization problems step by step online. Factor the expression 3x^2+19x+20. Factor the trinomial 3x^2+19x+20 of the form ax^2+bx+c, first, make the product of 3 and 20. Now, find two numbers that multiplied give us 60 and add up to 19. Rewrite the original expression. Factor 3x^2+15x+4x+20 by the greatest common divisor 3.

Final answer to the problem

$\left(x+5\right)\left(3x+4\right)$

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Function Plot

Plotting: $\left(x+5\right)\left(3x+4\right)$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Polynomial Factorization

They are a group of techniques that help us rewrite polynomial expressions as a product of factors.

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