Find the limit of $\frac{\left|2+x\right|-2}{x}$ as $x$ approaches 0

Step-by-step Solution

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Final answer to the problem

$\infty $
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Step-by-step Solution

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  • Solve using limit properties
  • Solve using direct substitution
  • Solve the limit using factorization
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  • Integrate by partial fractions
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Evaluate the limit $\lim_{x\to0}\left(\frac{\left|2+x\right|-2}{x}\right)$ by replacing all occurrences of $x$ by $0$

$\frac{\left|2+0\right|-2}{0}$

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$\frac{\left|2+0\right|-2}{0}$

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Learn how to solve limits by direct substitution problems step by step online. Find the limit of (abs(2+x)-2)/x as x approaches 0. Evaluate the limit \lim_{x\to0}\left(\frac{\left|2+x\right|-2}{x}\right) by replacing all occurrences of x by 0. Add the values 2 and 0. An expression divided by zero tends to infinity. As by directly replacing the value to which the limit tends, we obtain an indeterminate form, we must try replacing a value close but not equal to 0. In this case, since we are approaching 0 from the left, let's try replacing a slightly smaller value, such as -0.00001 in the function within the limit:.

Final answer to the problem

$\infty $

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Function Plot

Plotting: $\frac{\left|2+x\right|-2}{x}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Limits by Direct Substitution

Find limits of functions at a specific point by directly plugging the value into the function.

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