Final answer to the problem
$\sum_{n=0}^{\infty } \frac{{\left(-1\right)}^nt^{\left(5n+1\right)}}{\left(5n+1\right)\left(n!\right)}+C_0$
Got another answer? Verify it here!
Step-by-step Solution
Learn how to solve integrals of exponential functions problems step by step online. Find the integral int(e^(-t^5))dt. Rewrite the function e^{-t^5} as it's representation in Maclaurin series expansion. The power of a product is equal to the product of it's factors raised to the same power. Simplify \left(t^5\right)^n using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 5 and n equals n. We can rewrite the power series as the following.
Final answer to the problem
$\sum_{n=0}^{\infty } \frac{{\left(-1\right)}^nt^{\left(5n+1\right)}}{\left(5n+1\right)\left(n!\right)}+C_0$
