Final answer to the problem
$\frac{\left(2+1\right)^{26}}{26}- \frac{\left(0+1\right)^{26}}{26}$
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- Integrate by partial fractions
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1
Apply the formula: $\int\left(x+a\right)^ndx$$=\frac{\left(x+a\right)^{\left(n+1\right)}}{n+1}+C$, where $a=1$ and $n=25$
$\left[\frac{\left(x+1\right)^{\left(25+1\right)}}{25+1}\right]_{0}^{2}$
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$\left[\frac{\left(x+1\right)^{\left(25+1\right)}}{25+1}\right]_{0}^{2}$
Learn how to solve problems step by step online. Integrate the function (x+1)^25 from 0 to 2. Apply the formula: \int\left(x+a\right)^ndx=\frac{\left(x+a\right)^{\left(n+1\right)}}{n+1}+C, where a=1 and n=25. Simplify the expression. Evaluate the definite integral.
Final answer to the problem
$\frac{\left(2+1\right)^{26}}{26}- \frac{\left(0+1\right)^{26}}{26}$
