Final answer to the problem
$\frac{a^{3}\left(32a^{3}b^2+48a^2b-1\right)}{8}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Load more...
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1
Factor the polynomial $32a^7b^5+48a^6b^4-a^4b^3$ by it's greatest common factor (GCF): $a^{4}b^{3}$
Learn how to solve simplification of algebraic fractions problems step by step online.
$\frac{a^{4}b^{3}\left(32a^{3}b^2+48a^2b-1\right)}{8ab^3}$
Learn how to solve simplification of algebraic fractions problems step by step online. Simplify the expression (32a^7b^5+48a^6b^4-a^4b^3)/(8ab^3). Factor the polynomial 32a^7b^5+48a^6b^4-a^4b^3 by it's greatest common factor (GCF): a^{4}b^{3}. Simplify the fraction \frac{a^{4}b^{3}\left(32a^{3}b^2+48a^2b-1\right)}{8ab^3} by b^{3}. Simplify the fraction \frac{a^{4}\left(32a^{3}b^2+48a^2b-1\right)}{8a} by a.
Final answer to the problem
$\frac{a^{3}\left(32a^{3}b^2+48a^2b-1\right)}{8}$
