Integrate the function $x^2\sqrt{2x^2+1+x^4}\ln\left(x\right)$ from $1$ to $3$

Step-by-step Solution

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Final answer to the problem

$\frac{3^{3}\ln\left|3\right|}{3}- \frac{1^{3}\ln\left|1\right|}{3}-\frac{26}{9}$
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Step-by-step Solution

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  • Integrate by partial fractions
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1

The trinomial $2x^2+1+x^4$ is a perfect square trinomial, because it's discriminant is equal to zero

$\Delta=b^2-4ac=2^2-4\left(1\right)\left(1\right) = 0$

Learn how to solve definite integrals problems step by step online.

$\Delta=b^2-4ac=2^2-4\left(1\right)\left(1\right) = 0$

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Learn how to solve definite integrals problems step by step online. Integrate the function x^2ln(x)(2x^2+1x^4)^(1/2) from 1 to 3. The trinomial 2x^2+1+x^4 is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula. Factoring the perfect square trinomial. Cancel exponents 2 and 1.

Final answer to the problem

$\frac{3^{3}\ln\left|3\right|}{3}- \frac{1^{3}\ln\left|1\right|}{3}-\frac{26}{9}$

Exact Numeric Answer

$6.998622$

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Function Plot

Plotting: $x^2\sqrt{2x^2+1+x^4}\ln\left(x\right)$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

See formulas (3)

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