Final answer to the problem
$y=\frac{\sqrt{1-6x}\left(x^2+3\right)^2}{\left(x+3\right)^2-2}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Differential
- Find the derivative
- Find the integral
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Load more...
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1
Add and subtract $\displaystyle\left(\frac{b}{2a}\right)^2$
Learn how to solve completing the square problems step by step online.
$y=\frac{\sqrt{1-6x}\left(x^2+3\right)^2}{x^2+6x+7+\left(\frac{6}{2}\right)^2- \left(\frac{6}{2}\right)^2}$
Learn how to solve completing the square problems step by step online. Solve the rational equation y=((1-6x)^(1/2)(x^2+3)^2)/(x^2+6x+7). Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Divide 6 by 2. Divide 6 by 2. Calculate the power 3^2.
Final answer to the problem
$y=\frac{\sqrt{1-6x}\left(x^2+3\right)^2}{\left(x+3\right)^2-2}$
