$49a^4b^2\cdot5a^3b^3$
$-81a^2-125b^4$
$\left(\frac{2-\sqrt{\left(\left(-2.99\right)^2-5\right)}}{\left(-2.99\right)+3}\right)$
$( \frac { 0 + 4 } { 2 } ) ^ { 2 }$
$\int\left(\sqrt{196-x^2}\right)dx$
$\left(10d-h\right)^2$
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