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- Integrate by partial fractions
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- Product of Binomials with Common Term
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Rewrite the fraction $\frac{3x^3-x^2+6x-4}{\left(x^2+1\right)\left(x^2+2\right)}$ in $2$ simpler fractions using partial fraction decomposition
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$\frac{3x-3}{x^2+1}+\frac{2}{x^2+2}$
Learn how to solve problems step by step online. Find the integral int((3x^3-x^26x+-4)/((x^2+1)(x^2+2)))dx. Rewrite the fraction \frac{3x^3-x^2+6x-4}{\left(x^2+1\right)\left(x^2+2\right)} in 2 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{3x-3}{x^2+1}+\frac{2}{x^2+2}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{3x-3}{x^2+1}dx results in: \frac{3}{2}\ln\left(x^2+1\right)-3\arctan\left(x\right). Gather the results of all integrals.