Final answer to the problem
$\frac{64g^{6}h^{4}k^{12}-8h^{25}k^{15}}{8}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
The power of a product is equal to the product of it's factors raised to the same power
$\frac{64g^{9}h^{6}k^{12}}{8g^3h^2}-h^{25}k^{15}$
Learn how to solve combining like terms problems step by step online.
$\frac{64g^{9}h^{6}k^{12}}{8g^3h^2}-h^{25}k^{15}$
Learn how to solve combining like terms problems step by step online. Simplify ((4g^3h^2k^4)^3)/(8g^3h^2)-(h^5k^3)^5. The power of a product is equal to the product of it's factors raised to the same power. Simplify the fraction \frac{64g^{9}h^{6}k^{12}}{8g^3h^2} by g. Simplify the fraction \frac{64g^{6}h^{6}k^{12}}{8h^2} by h. Combine \frac{64g^{6}h^{4}k^{12}}{8}-h^{25}k^{15} in a single fraction.
Final answer to the problem
$\frac{64g^{6}h^{4}k^{12}-8h^{25}k^{15}}{8}$
