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Rewrite the integrand $e^{-x}\left(-4.5+0.5x+5e^x-\left(25-5x-0.25x^2\right)\right)$ in expanded form
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$\int_{0}^{10}\left(-29.5e^{-x}+5.5xe^{-x}+5+0.25x^2e^{-x}\right)dx$
Learn how to solve problems step by step online. Integrate the function e^(-x)(-4.5+0.5x5e^x-(25-5.0x-0.25x^2)) from 0 to 10. Rewrite the integrand e^{-x}\left(-4.5+0.5x+5e^x-\left(25-5x-0.25x^2\right)\right) in expanded form. Expand the integral \int_{0}^{10}\left(-29.5e^{-x}+5.5xe^{-x}+5+0.25x^2e^{-x}\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{10}-29.5e^{-x}dx results in: 29.5\cdot e^{-10}-29.5. The integral \int_{0}^{10}5.5xe^{-x}dx results in: -55\cdot e^{-10}-5.5\left(e^{-10}-1\right).