Factor the expression $81a^6b^4c^2-126a^5b^6c+49a^4b^8$

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Final answer to the problem

$a^{4}b^{4}\left(7b^{2}-9ac\right)^{2}$
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Step-by-step Solution

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1

Factor the polynomial $81a^6b^4c^2-126a^5b^6c+49a^4b^8$ by it's greatest common factor (GCF): $a^{4}b^{4}$

$a^{4}b^{4}\left(81a^2c^2-126ab^2c+49b^{4}\right)$

Learn how to solve logarithmic differentiation problems step by step online.

$a^{4}b^{4}\left(81a^2c^2-126ab^2c+49b^{4}\right)$

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Learn how to solve logarithmic differentiation problems step by step online. Factor the expression 81a^6b^4c^2-126a^5b^6c49a^4b^8. Factor the polynomial 81a^6b^4c^2-126a^5b^6c+49a^4b^8 by it's greatest common factor (GCF): a^{4}b^{4}. The trinomial \left(81a^2c^2-126ab^2c+49b^{4}\right) is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula. Factoring the perfect square trinomial.

Final answer to the problem

$a^{4}b^{4}\left(7b^{2}-9ac\right)^{2}$

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Plotting: $a^{4}b^{4}\left(7b^{2}-9ac\right)^{2}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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