$9v^2+3v+8v^2-v^3+v$
$1-9m^2n^4x^6y^8$
$\lim_{x\to0}\left(\frac{\left(x+1\right)^{\left(3x\right)}}{x^{3x}}\right)$
$x^4+2x^3-3yx$
$\left(-\frac{5}{9}\right)-0.7\infty$
$5.9-5.67$
$\left(1+2\tan\:\left(x\right)\right)^2\:$
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