Final answer to the problem
$y=\frac{-2x}{\ln\left(x\right)+C_0}+x$
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Step-by-step Solution
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- Exact Differential Equation
- Linear Differential Equation
- Separable Differential Equation
- Homogeneous Differential Equation
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
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1
Grouping the terms of the differential equation
$2dy=\frac{x^2+y^2}{x^2}dx$
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$2dy=\frac{x^2+y^2}{x^2}dx$
Learn how to solve problems step by step online. Solve the differential equation 2x^2dy=(x^2+y^2)dx. Grouping the terms of the differential equation. Divide both sides of the equation by dx. Rewrite the differential equation. We can identify that the differential equation \frac{dy}{dx}=\frac{x^2+y^2}{2x^2} is homogeneous, since it is written in the standard form \frac{dy}{dx}=\frac{M(x,y)}{N(x,y)}, where M(x,y) and N(x,y) are the partial derivatives of a two-variable function f(x,y) and both are homogeneous functions of the same degree.
Final answer to the problem
$y=\frac{-2x}{\ln\left(x\right)+C_0}+x$
