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- Integrate by partial fractions
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- Weierstrass Substitution
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- Product of Binomials with Common Term
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Rewrite the integrand $\left(w^2+\cos\left(4w^3-3\right)^2\right)\sec\left(4w^3-3\right)^2$ in expanded form
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$\int\left(w^2\sec\left(4w^3-3\right)^2+\cos\left(4w^3-3\right)^2\sec\left(4w^3-3\right)^2\right)dw$
Learn how to solve integral calculus problems step by step online. Find the integral int((w^2+cos(4w^3-3)^2)sec(4w^3-3)^2)dw. Rewrite the integrand \left(w^2+\cos\left(4w^3-3\right)^2\right)\sec\left(4w^3-3\right)^2 in expanded form. Expand the integral \int\left(w^2\sec\left(4w^3-3\right)^2+\cos\left(4w^3-3\right)^2\sec\left(4w^3-3\right)^2\right)dw into 2 integrals using the sum rule for integrals, to then solve each integral separately. Applying the trigonometric identity: \cos\left(\theta\right)\cdot\sec\left(\theta\right)=1. The integral \int w^2\sec\left(4w^3-3\right)^2dw results in: \frac{1}{12}\tan\left(4w^3-3\right).
