Final answer to the problem
$7a^2-4ab+2b^2+\left(a+2b\right)^2-\left(-2b\right)^2$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Combining like terms $\left(2a-b\right)^2$ and $\left(2a-b\right)^2$
$2\left(2a-b\right)^2+\left(a+2b\right)^2-\left(a-2b\right)^2$
Learn how to solve integrals of rational functions problems step by step online.
$2\left(2a-b\right)^2+\left(a+2b\right)^2-\left(a-2b\right)^2$
Learn how to solve integrals of rational functions problems step by step online. Reduce like terms (2a-b)^2+(2a-b)^2(a+2b)^2-(a-2b)^2. Combining like terms \left(2a-b\right)^2 and \left(2a-b\right)^2. Expand \left(2a-b\right)^2. The power of a product is equal to the product of it's factors raised to the same power. Multiply the single term 2 by each term of the polynomial \left(4a^2-4ab+b^2\right).
Final answer to the problem
$7a^2-4ab+2b^2+\left(a+2b\right)^2-\left(-2b\right)^2$
