Solve the differential equation $ty^{\prime}-3y=t^4$

Step-by-step Solution

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Final answer to the problem

$y=\left(t+C_0\right)t^{3}$
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Step-by-step Solution

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  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
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Rewrite the differential equation using Leibniz notation

$t\frac{dy}{dt}-3y=t^4$

Learn how to solve differential equations problems step by step online.

$t\frac{dy}{dt}-3y=t^4$

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Unlock the first 3 steps of this solution

Learn how to solve differential equations problems step by step online. Solve the differential equation ty^'-3y=t^4. Rewrite the differential equation using Leibniz notation. Divide all the terms of the differential equation by t. Simplifying. We can identify that the differential equation has the form: \frac{dy}{dx} + P(x)\cdot y(x) = Q(x), so we can classify it as a linear first order differential equation, where P(t)=\frac{-3}{t} and Q(t)=t^{3}. In order to solve the differential equation, the first step is to find the integrating factor \mu(x).

Final answer to the problem

$y=\left(t+C_0\right)t^{3}$

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Function Plot

Plotting: $y=\left(t+C_0\right)t^{3}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Equations

A differential equation is a mathematical equation that relates some function with its derivatives.

Used Formulas

See formulas (1)

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