Final answer to the problem
$-x-5+\frac{20}{5-x}$
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Step-by-step Solution
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- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Divide $x^2-5$ by $5-x$
$\begin{array}{l}\phantom{-x\phantom{;}+5;}{-x\phantom{;}-5\phantom{;}\phantom{;}}\\-x\phantom{;}+5\overline{\smash{)}\phantom{;}x^{2}\phantom{-;x^n}-5\phantom{;}\phantom{;}}\\\phantom{-x\phantom{;}+5;}\underline{-x^{2}+5x\phantom{;}\phantom{-;x^n}}\\\phantom{-x^{2}+5x\phantom{;};}\phantom{;}5x\phantom{;}-5\phantom{;}\phantom{;}\\\phantom{-x\phantom{;}+5-;x^n;}\underline{-5x\phantom{;}+25\phantom{;}\phantom{;}}\\\phantom{;-5x\phantom{;}+25\phantom{;}\phantom{;}-;x^n;}\phantom{;}20\phantom{;}\phantom{;}\\\end{array}$
2
Resulting polynomial
$-x-5+\frac{20}{5-x}$
Final answer to the problem
$-x-5+\frac{20}{5-x}$
