$\lim_{x\to-4}\left(\frac{x^3+x^2-6x}{x^2+3x}\right)$

$-1^2-\left(-1\right)^3$

$mercury$

$v\left(x\right)=3.94\cdot x-0.125\cdot x^3$

$\frac{d}{dx}\left(x+y-cos\left(xy\right)=0\right)$

$\frac{dy}{dx}\left(x^2+2x+2y^2=1\right)$

$\left(a^5+5\right)\left(a^5-10\right)$